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Sulfuric Acid Essay Research Paper Sulfuric Acid

Sulfuric Acid Essay, Research Paper


Sulfuric Acid Industry in Ontario


Among the many plants in Ontario where sulfuric acid is


produced, there are three major plant locations that should


be noted on account of their greater size. These are: (1)


Inco. – Sudbury, (2) Noranda Mines Ltd. – Welland, and (3) Sulfide – Ontario


There are a number of factors which govern the location


of each manufacturing plant. Some of these factors that have


to be considered when deciding the location of a Sulfuric Acid plant are:


a. Whether there is ready access to raw materials;


b. Whether the location is close to major transportation routes;


c. Whether there is a suitable work force in the area for


plant construction and operation;


d. Whether there is sufficient energy resources readily available;


e. Whether or not the chemical plant can carry out its


operation without any unacceptable damage to the environment.


Listed above are the basic deciding factors that govern


the location of a plant. The following will explain in


greater detail why these factors should be considered.1) Raw Materials


The plant needs to be close to the raw materials that


are involved in the production of sulfuric acid such as


sulfur, lead, copper, zinc sulfides, etc..2) Transportation


A manufacturer must consider proximity to transpor-


tation routes and the location of both the source of raw


materials and the market for the product. The raw


materials have to be transported to the plant, and the


final product must be transported to the customer or


distributor. Economic pros and cons must also be thought


about. For example, must sulfuric plants are located


near the market because it costs more to transport


sulfuric acid than the main raw materials, sulfur.


Elaborate commission proof container are required for the


transportation of sulfuric acid while sulfur can be much


more easily transported by truck or railway car.


3) Human Resources For a sulfuric acid plant to operate, a


large work force will obviously be required. The plant must


employ chemists, technicians, administrators, computer


operators, and people in sales and marketing. A large number


of workers will also be required for the daily operation of


the plant. A work force of this diversity is therefore likely


to be found only near major centres of population.4) Energy Demands


Large amounts of energy will also be required for the


production of many industrial chemicals. Thus, proximity


to a plentiful supply of energy is often a determining


factor in deciding the plant’s location. 5) Environmental Concerns


Most importantly, however, concerns about the


environment must be carefully taken into consideration.


The chemical reaction of changing sulfur and other


substances to sulfuric acid results in the formation of


other substances like sulfur dioxide. This causes acid


rain. Therefore, there is a big problem about sulfuric


plants causing damage to our environment as the plant is


a source of sulfur emission leading to that of acid rain.6) Water Supplies


Still another factor is the closeness of the location


of the plants to water supplies as many manufacturing


plants use water for cooling purposes.


In addition to these factors, these questions must also


be answered: Is land available near the proposed site at a


reasonable cost? Is the climate of the area suitable? Are


the general living conditions in the area suitable for the


people involved who will be relocating in the area? Is there


any suggestions offered by governments to locate in a particular region?


The final decision on where the sulfuric acid plant


really involves a careful examination and a compromise among


all of the factors that have been discussed above.Producing Sulfuric Acid


Sulfuric acid is produced by two principal processes–


the chamber process and the contact process.


The contact process is the current process being used to


produce sulfuric acid. In the contact process, a purified


dry gas mixture containing 7-10% sulfur dioxide and 11-14%


oxygen is passed through a preheater to a steel reactor


containing a platinum or vanadium peroxide catalyst. The


catalyst promotes the oxidation of sulfur dioxide to


trioxide. This then reacts with water to produce sulfuric


acid. In practice, sulfur trioxide reacts not with pure


water but with recycled sulfuric acid.The reactions are: 2SO2 + O2 –* 2SO3


SO3 + H2O –* H2SO4 The product of the contact plants is 98-100% acid. This


can either be diluted to lower concentrations or made


stronger with sulfur trioxide to yield oleums. For the


process, the sources of sulfur dioxide may be produced from


pure sulfur, from pyrite, recovered from smelter operations


or by oxidation of hydrogen sulfide recovered from the


purification of water gas, refinery gas, natural gas and other fuels.


Battery Acid Industry Many industries depend on sulfuric acid. Among these


industries is the battery acid industry.


The electric battery or cell produces power by means of


a chemical reaction. A battery can be primary or secondary.


All batteries, primary or secondary, work as a result of a


chemical reaction. This reaction produces an electric


current because the atoms of which chemical elements are


made, are held together by electrical forces when they react to form compounds.


A battery cell consists of three basic parts; a


positively charged electrode, called the cathode, a


negatively charged electrode, called the anode, and a


chemical substance, called an electrolyte, in which the


electrodes are immersed. In either a wet or dry cell,


sufficient liquid must be present to allow the chemical reactions to take place.


Electricity is generated in cells because when any of


these chemical substances is dissolved in water , its


molecules break up and become electrically charged ions.


Sulfuric acid is a good example. Sulfuric acid, H2SO4, has


molecules of which consist of two atoms of hydrogen, one of


sulfur and four oxygen. When dissolved in water, the


molecules split into three parts, the two atoms of hydrogen


separate and in the process each loses an electron, becoming


a positively charged ion (H+). The sulfur atom and the four


atoms of oxygen remain together as a sulfate group (SO4), and


acquire the two electrons lost by t

he hydrogen atoms, thus


becoming negatively charged (SO4–). These groups can


combine with others of opposite charge to form other compounds.


The lead-acid cell uses sulfuric acid as the


electrolyte. The lead-acid storage battery is the most


common secondary battery used today, and is typical of those


used in automobiles. The following will describe both the


charging and discharging phase of the lead-storage battery


and how sulfuric acid, as the electrolyte, is used in the


process. The lead storage battery consists of two electrodes


or plates, which are made of lead and lead peroxide and are


immersed in an electrolytic solution of sulfuric acid. The


lead is the anode and the lead peroxide is the cathode. When


the battery is used, both electrodes are converted to lead


sulfate by the following process. At the sulfate ion that is


present in the solution from the sulfuric acid. At the


cathode, meanwhile, the lead peroxide accepts two electrons


and releases the oxygen; lead oxide is formed first, and then


lead joins the sulfate ion to form lead sulfate. At the same


time, four hydrogen ions released from the acid join the


oxygen released from the lead peroxide to form water. When


all the sulfuric acid is used up, the battery is “discharged”


produces no current. The battery can be recharged by passing


the current through it in the opposite direction. This


process reverses all the previous reactions and forms lead at


the anode and lead peroxide at the cathode.Proposed Problem


i) The concentration of sulfuric acid is 0.0443 mol/L.


The pH is: No. mol of hydrogen ions = 0.0443 mol/L x 2


= 0.0886 mol/L hydrogen ions pH = – log [H]


= – log (0.0886) = – (-1.0525) = 1.05 Therefore, pH is 1.05.


ii) The amount of base needed to neutralize the lake water is:


volume of lake = 2000m x 800m x 50m


= 800,000,000 m3 or 8×108 m3


since 1m3=1000L, therefore 8×1011 L


0.0443 mol/L x 8×1011 = 3.54 x 1010 mol of H2SO4 in water


# mol NaOH = 3.54 x 1010 mol H2SO4 x 2 mol NaOH


1 mol H2SO4


= 7.08 x 1010 mol of NaOH needed


Mass of NaOH = 7.08 x 1010 mol NaOH x 40 g NaOH


1 mol NaOH


= 2.83 x 1012 g NaOH or 2.83 x 109 kg NaOH


Therefore a total of 2.83 x 1012 g of NaOH is needed to


neutralize the lake water.iii) The use of sodium hydroxide versus limestone to


neutralize the lake water:


Sodium hydroxide: Sodium hydroxide produces water when


reacting with an acid, it also dissolves in water quite


readily. When using sodium hydroxide to neutralize a lake,


there may be several problems. One problem is that when


sodium hydroxide dissolves in water, it gives off heat and


this may harm aquatic living organisms. Besides this, vast


amounts of sodium hydroxide is required to neutralize a lake


therefore large amounts of this substance which is corrosive


will have to be transported. This is a great risk to the


environment if a spill was to occur.


The following equation shows that water is produced when


using sodium hydroxide.2NaOH + H2SO4 –* Na2 SO4 + 2H2O


Limestone: Another way to neutralize a lake is by


liming. Liming of lakes must be done with considerable


caution and with an awareness that the aquatic ecosystem


will not be restored to its original pre-acidic state even


though the pH of water may have returned to more normal


levels. When limestone dissolves in water it produces carbon


dioxide. This could be a problem since a higher content of


carbon dioxide would mean a lowered oxygen content especially


when much algae growth is present. As a result, fish and


other organisms may suffer. Limestone also does not dissolve


as readily as sodium hydroxide thus taking a longer period of


time to react with sulfuric acid to neutralize the lake. The


equation for the neutralization using limestone is as follows:


Ca CO3 + H2SO4 –* CaSO4 + H2O.


iv) The effect of the Acid or excessive Base on the plant and animal life:


You will probably find that there aren’t many aquatic


living organisms in waters that are excessively basic or


acidic. A high acidic or basic content in lakes kill fishes


and other aquatic species. Prolonged exposure to acidic or


excessively basic conditions can lead to reproductive failure


and morphological aberration of fish. A lowered pH tends to


neutralize toxic metals. The accumulation of such metals in


fish contaminates food chains of which we are a part as these


metals can make fish unfit for human consumption.


Acidification of a lake causes a reduction of the production


of phytoplankton (which is a primary producer) as well as in


the productivity of the growth of many other aquatic plants.


In acidic conditions, zooplankton species will probably


becompletely eliminated. In addition, bacterial


decomposition of dead matter is seriously retarded in


acidified lake waters. Other effects of acidic conditions


arean overfertilization of algae and other microscopic plant


lifecausing algae blooms. Overgrowth of these consumes


quickly most of the oxygen in water thus causing other life


forms to die from oxygen starvation.


When there are excessive base or acid in waters, not


only do aquatic organisms get affected but animals who depend


on aquatic plants to survive will starve too, since few


aquatic plants survive in such conditions. Therefore each


organism in the aquatic ecosystem is effected by excessive


basic or acidic conditions because anything affecting one


organism will affect the food chain, sending repercussions


throughout the entire ecosystem.


v) The factors that govern this plant’s location, if this


plant employs 40% of the towns people:


The major factors that would govern this plant’s


location would be whether there is ready access to raw


materials; whether the location is close to major


transportation routes; whether energy resources are readily


available and if there is an adequate water supply in the


area. Since this plant would employ 40% of the towns people,


the plant should be close to the town while still far enough


so that in case of any leakage of the plant, the town will be


within a safe distance of being severely affected. The


factor of whether the general living conditions in the area


are suitable for the workers should also be considered as well.

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